x^2+57x=1862

Solution for x^2+57x=1862 equation:

x^2+57x=1862

We move all terms to the left:

x^2+57x-(1862)=0

a = 1; b = 57; c = -1862;
Δ = b2-4ac
Δ = 572-4·1·(-1862)
Δ = 10697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-\sqrt{10697}}{2*1}=\frac{-57-\sqrt{10697}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+\sqrt{10697}}{2*1}=\frac{-57+\sqrt{10697}}{2}
$